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[drivers][ofw] Fixed fdt_scan_memory() memory adjustment bug #8853

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Merged
merged 2 commits into from
Apr 27, 2024

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liYony
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@liYony liYony commented Apr 24, 2024

拉取/合并请求描述:(PR description)

[

在调用fdt_scan_memory对设备树的内存进行解析后,会根据保留内存对整个内存重新做出一些调整。如下图(添加了一些打印信息):

image

如图所示,调整后出现了一个起始地址等于结束地址的一个无效mem_region。

[I/rtdm.ofw]   (NULL)           [0x00000000441581a0, 0x00000000441581a0]

排查发现是对case 0情况的判断条件不妥。

/*
             * case 0:                      case 1:
             *  +------------------+             +----------+
             *  |      memory      |             |  memory  |
             *  +---+----------+---+         +---+----------+---+
             *      | reserved |             |     reserved     |
             *      +----------+             +---+----------+---+
             *
             * case 2:                      case 3:
             *  +------------------+                +------------------+
             *  |      memory      |                |      memory      |
             *  +--------------+---+------+  +------+---+--------------+
             *                 | reserved |  | reserved |
             *                 +----------+  +----------+
             */

如果出现了一个res_region->start = region->start 和 res_region->end < region->end 的情况。

+------------------+
|      memory      |
+----------+-------+
| reserved |    
+----------+    

按照目前的代码,是符合case 0 情况的,那么这里调整后会出现两个mem_region,其中一个的起始地址等于结束地址。显然这是不合理的,对于这种情况,直接走case 3 情况处理即可。而且这里这个mem_region将会在下一次遍历为mem_region->name赋值为RT_NULL,那这样做其实也是会影响外层for循环的执行的(for (no = 0; region->name; ++region){})。

这里我做了一个验证,我故意多commit了几个内存保留区域(基于qemu-virt64-aarch64)。

image

结果,并没有为0x46000000~0x46001000这段空间进行调整,肯定是不符合要求的。

image

按照我目前pr的修改方式,可以解决这个问题。

image

]

当前拉取/合并请求的状态 Intent for your PR

必须选择一项 Choose one (Mandatory):

  • 本拉取/合并请求是一个草稿版本 This PR is for a code-review and is intended to get feedback
  • 本拉取/合并请求是一个成熟版本 This PR is mature, and ready to be integrated into the repo

代码质量 Code Quality:

我在这个拉取/合并请求中已经考虑了 As part of this pull request, I've considered the following:

  • 已经仔细查看过代码改动的对比 Already check the difference between PR and old code
  • 代码风格正确,包括缩进空格,命名及其他风格 Style guide is adhered to, including spacing, naming and other styles
  • 没有垃圾代码,代码尽量精简,不包含#if 0代码,不包含已经被注释了的代码 All redundant code is removed and cleaned up
  • 所有变更均有原因及合理的,并且不会影响到其他软件组件代码或BSP All modifications are justified and not affect other components or BSP
  • 对难懂代码均提供对应的注释 I've commented appropriately where code is tricky
  • 代码是高质量的 Code in this PR is of high quality
  • 已经使用formatting 等源码格式化工具确保格式符合RT-Thread代码规范 This PR complies with RT-Thread code specification

@mysterywolf mysterywolf reopened this Apr 24, 2024
@BernardXiong BernardXiong requested a review from polarvid April 25, 2024 11:30
@polarvid
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其实这个 case 逻辑可以化简一点的. 参考

static int _remove_overlapped_varea(rt_varea_t existed, char *unmap_start, rt_size_t unmap_len)
{
int error;
char *ex_start = existed->start;
char *ex_end = ex_start + existed->size;
char *unmap_end = unmap_start + unmap_len;
if (ex_start < unmap_start)
{
if (ex_end > unmap_end)
error = _split_varea(existed, ex_end, unmap_start, unmap_end, unmap_len);
else
error = _shrink_varea(existed, ex_start, unmap_start - ex_start);
}
else if (ex_end > unmap_end)
error = _shrink_varea(existed, unmap_end, ex_end - unmap_end);
else
{

之后大概就是这样

            if (res_region->start > region->start)
            {
                if (res_region->end < region->end)
                {
                    /* case 0 */
                }
            }
            else
            {
                if (res_region->end >= region->end)
                {
                    if (res_region->start <= region->end)
                    {
                        /* case 2 */
                    }
                    else
                    {
                        /* case 1 */
                    }
                }

                if (res_region->end >= region->start)
                {
                    /* case 3 */
                }
            }

@liYony
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liYony commented Apr 26, 2024

其实这个 case 逻辑可以化简一点的. 参考

static int _remove_overlapped_varea(rt_varea_t existed, char *unmap_start, rt_size_t unmap_len)
{
int error;
char *ex_start = existed->start;
char *ex_end = ex_start + existed->size;
char *unmap_end = unmap_start + unmap_len;
if (ex_start < unmap_start)
{
if (ex_end > unmap_end)
error = _split_varea(existed, ex_end, unmap_start, unmap_end, unmap_len);
else
error = _shrink_varea(existed, ex_start, unmap_start - ex_start);
}
else if (ex_end > unmap_end)
error = _shrink_varea(existed, unmap_end, ex_end - unmap_end);
else
{

之后大概就是这样

            if (res_region->start > region->start)
            {
                if (res_region->end < region->end)
                {
                    /* case 0 */
                }
            }
            else
            {
                if (res_region->end >= region->end)
                {
                    if (res_region->start <= region->end)
                    {
                        /* case 2 */
                    }
                    else
                    {
                        /* case 1 */
                    }
                }

                if (res_region->end >= region->start)
                {
                    /* case 3 */
                }
            }

OK 感谢建议,我修改一下

@polarvid
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其实这个 case 逻辑可以化简一点的. 参考

static int _remove_overlapped_varea(rt_varea_t existed, char *unmap_start, rt_size_t unmap_len)
{
int error;
char *ex_start = existed->start;
char *ex_end = ex_start + existed->size;
char *unmap_end = unmap_start + unmap_len;
if (ex_start < unmap_start)
{
if (ex_end > unmap_end)
error = _split_varea(existed, ex_end, unmap_start, unmap_end, unmap_len);
else
error = _shrink_varea(existed, ex_start, unmap_start - ex_start);
}
else if (ex_end > unmap_end)
error = _shrink_varea(existed, unmap_end, ex_end - unmap_end);
else
{

之后大概就是这样

            if (res_region->start > region->start)
            {
                if (res_region->end < region->end)
                {
                    /* case 0 */
                }
            }
            else
            {
                if (res_region->end >= region->end)
                {
                    if (res_region->start <= region->end)
                    {
                        /* case 2 */
                    }
                    else
                    {
                        /* case 1 */
                    }
                }

                if (res_region->end >= region->start)
                {
                    /* case 3 */
                }
            }

OK 感谢建议,我修改一下

其实这个 case 逻辑可以化简一点的. 参考

static int _remove_overlapped_varea(rt_varea_t existed, char *unmap_start, rt_size_t unmap_len)
{
int error;
char *ex_start = existed->start;
char *ex_end = ex_start + existed->size;
char *unmap_end = unmap_start + unmap_len;
if (ex_start < unmap_start)
{
if (ex_end > unmap_end)
error = _split_varea(existed, ex_end, unmap_start, unmap_end, unmap_len);
else
error = _shrink_varea(existed, ex_start, unmap_start - ex_start);
}
else if (ex_end > unmap_end)
error = _shrink_varea(existed, unmap_end, ex_end - unmap_end);
else
{

之后大概就是这样

            if (res_region->start > region->start)
            {
                if (res_region->end < region->end)
                {
                    /* case 0 */
                }
            }
            else
            {
                if (res_region->end >= region->end)
                {
                    if (res_region->start <= region->end)
                    {
                        /* case 2 */
                    }
                    else
                    {
                        /* case 1 */
                    }
                }

                if (res_region->end >= region->start)
                {
                    /* case 3 */
                }
            }

OK 感谢建议,我修改一下

你也别完全用这个,我没细看的,哈哈哈。

            if (res_region->start > region->start)
            {
                if (res_region->end < region->end)
                {
                    /* case 0 */
                }
            }
            else /* if res_region->start <= region->start */
            {
                if (res_region->end >= region->end)
                {
                    /* case 1 */
                }

                if (res_region->end >= region->start)
                {
                    /* case 3 */
                }
            }

            if (res_region->start <= region->end && res_region->end >= region->end)
            {
                /* case 2 */
            }

@polarvid
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可以用这个改一个 utest 跑一下 examples/utest/testcases/mm/mm_memblock_tc.c

@liYony
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liYony commented Apr 26, 2024

重新修改了一下内存调整的逻辑,我这边以qemu-virt64-aarch64做了一下测试:

image

效果完美!测试通过!

@liYony
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liYony commented Apr 26, 2024

可以用这个改一个 utest 跑一下 examples/utest/testcases/mm/mm_memblock_tc.c

utest我还真没用过

@BernardXiong BernardXiong merged commit d30c8b3 into RT-Thread:master Apr 27, 2024
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4 participants